I have played around with the concept of Sharpe Ratio and posted this some time ago on another forum.
Suppose you have System1 with an annualized rate of return over riskless rate m1, and with an annualized standard deviation of s1. Then, your Sharpe Ratio is SR1 = m1/s1. Now, you also have System2 with a Sharpe Ratio of SR2 = m2/s2. SUPPOSE THE TWO SYSTEMS HAVE A SERIAL CORRELATION OF 0. Now, what is going to be the Sharpe Ratio of 1+2 ?
SR = (m1+ m2) / (SQRT(s1^2 + s2 ^ 2))
Let's put : s2 = k *s1
k is the weight you are going to give to system 2 if system1 has a weight of 1.
then, we have : m1 = SR1 * s1 and m2 = SR2 * k * s1, so
SR = (SR1 + k SR2) / (SQRT(1 + k^2)
We then ask the following question. On what condition is SR maximum? In other words, how much of System2 should we trade in order to have the best final Sharpe Ratio?
Answer : for kmax = SR2 / SR1 (i) (you can check by yourself

)
When you think about it, the answer is pretty intuitive. The higher the Sharpe Ratio of your system, the more weight it should have in the final system.
Now, thanks to (i) we can calculate the final Sharpe Ratio :
SR = SR1 * SQRT(1 + (SR2 ^ 2 / SR1 ^ 2)) (ii)
We can check that SR > SR1 and that SR > SR2 , which shows the value of diversification.
Now let's illustrate what we've found. Suppose we trade n systems that all have a Sharpe Ratio of SR0. TAKEN 2 by 2, ALL THE SYSTEM PAIRS HAVE A PAIRWISE CORRELATION OF 0. Now what is going to be the Sharpe Ratio (SR(n)) of our mega system if we use an optimal weighting? Using (ii), we find :
1 system : SR(1) = SR0
2 systems : we trade one system with Sharpe Ratio = SR0, and one system with Sharpe Ratio SR0. Then, using (ii), we have SR(2) = SR0 * SQRT(2).
3 systems : we trade on system with Sharpe Ratio = SR0 * SQRT(2), and one system with Sharpe Ratio SR0. Then, using (2), we have SR(2) = SR0 * SQRT(3).
If you continue, you will find out (and can easily prove!) that :
n systems : SR(n) = SR0 * SQRT(n) (iii)
In other words, if :
- all your systems have the same Sharpe Ratio
- your systems have no 2 by 2 correlation
- you mix your systems at the optimal weighting (given by (i))
(a lot if ifs!)
then, YOUR SHARPE RATIO GROWS WITH THE SQUARE ROOT OF THE NUMBER OF THE SYSTEMS YOU TRADE.
I understand that this is just a simple case of the mean / variance optimization, but I found (iii) simple and easy to remember!